The following code snippet is for finding maximum value among three numbers.
Example 1: Using If and Else statement
[VB.Net]
Private Function Getmaximum(ByVal a As Integer, ByVal b As Integer, ByVal c As Integer) As Integer Dim MaxValue As Integer If a > b Then If a > c Then MaxValue = a Else MaxValue = c End If Else If b > c Then MaxValue = b Else MaxValue = c End If End If Return MaxValue End Function
[C#.Net]
private int Getmaximum(int a, int b, int c) { int MaxValue = 0; if (a > b) { if (a > c) { MaxValue = a; } else { MaxValue = c; } } else { if (b > c) { MaxValue = b; } else { MaxValue = c; } } return MaxValue; }
Example 2: Using List
Our valuable user James Tweedie suggest the another method to use the List and var objects(below in the comment). var type is added in the visual studio 2008 version.
public double MinimumOf3(double d1, double d2, double d3) { var nums = new []{d1, d2, d3}.ToList(); nums.Sort(); return nums[0]; } public double MaximumOf3(double d1, double d2, double d3) { var nums = new []{d1, d2, d3}.ToList(); nums.Sort(); return nums[2]; }
The Sort() method will sort the values in the list object in the ascending order Than you can get the lower limit and upper limit values to find out the minimum and maximum value correspondingly.
Hi, This also works and avoids if..then..else:
public double MinimumOf3(double d1, double d2, double d3)
{
var nums = new []{d1, d2, d3}.ToList();
nums.Sort();
return nums[0];
}
public double MaximumOf3(double d1, double d2, double d3)
{
var nums = new []{d1, d2, d3}.ToList();
nums.Sort();
return nums[2];
}
Can also be easily extended for more numbers. Also easy to generalise if needed (I only have 3 doubles in my project).
Hi thanks James.
I have added your suggested method in the above content.
Thanks
Hi Hirendra,
Thanks for the inclusion and the expanded explanation.
This method can also be used as the basis to calculate statistics, if needed!