Get the file name from the full path in VB.Net

In the below there are two methods that can be use to extract the file name from the full file path.

Using System.IO.Path.GetFileName
The following method is using the System.IO.Path.GetFileName that returns the file name and extension of the specified path string.

Private Function GetFileName(ByVal path As String) As String
   Dim _filename As String = System.IO.Path.GetFileName(path)
   Return _filename
End Function

Using Split() method

In this method we are splitting the specified path string with the separators and pick the last string from the returned array of spitted string.

Private Function GetFileName_OtherMethod(ByVal path As String) As String
    Dim _filename As String = ""
    Dim sep() As Char = {"/", "\", "//"}
    _filename = path.Split(sep).Last()
    Return _filename
End Function